2^x+2^(x+1)+2^(x+2)=28

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Solution for 2^x+2^(x+1)+2^(x+2)=28 equation: 



2^x+2^(x+1)+2^(x+2)=28

We move all terms to the left:

2^x+2^(x+1)+2^(x+2)-(28)=0

We move all terms containing x to the left, all other terms to the right

2^x+2^(x+1)+2^(x+2)=28

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